F=m*((v^2)/r)
Therefore (18.1^2m/s)/80m*3800=F
Therefore F=15561N
A 3800 kg car travels around an unbanked corner at the recommended speed of 65 km/hr. the radius of curvature is 80 m.
a) what is the force that the road exerts on the car to keep it in motion around the corner?
b) what force would the road need to exert if the car was traveling at 100 km/hr?
1 answer
1 answer