Asked by koram
A ball is shot from the top of a building with an initial velocity of 16m/s at an angle θ = 43∘ above the horizontal.
Part A
What are the horizontal and vertical components of the initial velocity?
If a nearby building is the same height and 55m away, how far below the top of the building will the ball strike the nearby building?
Part A
What are the horizontal and vertical components of the initial velocity?
If a nearby building is the same height and 55m away, how far below the top of the building will the ball strike the nearby building?
Answers
Answered by
bobpursley
horizontal=16cos43
vertical=16sin43
vertical=16sin43
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