A ball is shot from the top of a building with an initial velocity of 16m/s at an angle θ = 43∘ above the horizontal.

Question

Part A
What are the horizontal and vertical components of the initial velocity?
If a nearby building is the same height and 55m away, how far below the top of the building will the ball strike the nearby building?

Answer 1

horizontal=16cos43
vertical=16sin43