Question
A ball is shot from the ground straight up into the air with initial velocity of
45 ft/sec. Assuming that the air resistance can be ignored, how high does it go? HINT: The acceleration due to gravity is 32 ft per second squared.
45 ft/sec. Assuming that the air resistance can be ignored, how high does it go? HINT: The acceleration due to gravity is 32 ft per second squared.
Answers
oobleck
v = 45-32t
max height is when v=0
Now use that in
h = 45t - 16t^2
max height is when v=0
Now use that in
h = 45t - 16t^2