Asked by Elizabeth
                Aaron has two types do iodine in his lab. He has brand 213 iodine, which costs 36 cents per ounce. He also has brand 856 iodine, which costs 1.58$ per ounce. How many ounces of brand 213 should be used if he has 63 ounces of brand 856 and wants to make a mixture that costs approximately 0.53$ an ounce
            
            
        Answers
                    Answered by
            Steve
            
    the value of the parts must add up to the value of the whole.
If there are x oz. of brand 213, then
.36x + 1.58*63 = .53(x+63)
x = 389.12
Seems reasonable, since the cost of the mixture is much closer to that of the cheap brand; he'd need more of the cheap stuff than the costly one.
    
If there are x oz. of brand 213, then
.36x + 1.58*63 = .53(x+63)
x = 389.12
Seems reasonable, since the cost of the mixture is much closer to that of the cheap brand; he'd need more of the cheap stuff than the costly one.
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