Asked by Miranda
a rubber ball is thrown downwards off a balcony. after it travels 55m it has a speed of 46.5m/s. what is the initial velocity
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*d = 46.5^2
Vo^2 + 19.6*55 = 2162
Vo^2 = 2162 - 1078 = 1084
Vo = 32.92 m/s.
Vo^2 + 19.6*55 = 2162
Vo^2 = 2162 - 1078 = 1084
Vo = 32.92 m/s.
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