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Find the temperature at which the reaction below is spontaneous given this data: Hfo of NH3(g) = - 46 kJ/mol, So of NH3(g) = 19...Asked by Amandeep
Find the temperature at which the reaction below is spontaneous given this data:
Hf^o of NH3(g) = - 46 kJ/mol, S^o of NH3(g) = 192.5 J/mol·K, S^o of N2(g) = 191.5 J/mol·K,
S^o of H2(g) = 130.6 J/mol·K.
N2(g) + 3H2(g) <-----> 2NH3(g)
Hf^o of NH3(g) = - 46 kJ/mol, S^o of NH3(g) = 192.5 J/mol·K, S^o of N2(g) = 191.5 J/mol·K,
S^o of H2(g) = 130.6 J/mol·K.
N2(g) + 3H2(g) <-----> 2NH3(g)
Answers
Answered by
DrBob222
delta G = delta H - TdeltaS
delta H you have.
delta S<sub>rxn</sub> = S<sub>products</sub> - S<sub>reactants</sub>
Solve for T which will give a negative G.
delta H you have.
delta S<sub>rxn</sub> = S<sub>products</sub> - S<sub>reactants</sub>
Solve for T which will give a negative G.