Asked by Ericka
Find the temperature at which the reaction below is spontaneous given this data:
Hfo of NH3(g) = - 46 kJ/mol, So of NH3(g) = 192.5 J/mol·K, So of N2(g) = 191.5 J/mol·K,
So of H2(g) = 130.6 J/mol·K.
N2(g) + 3H2(g) ßà 2NH3(g)
Hfo of NH3(g) = - 46 kJ/mol, So of NH3(g) = 192.5 J/mol·K, So of N2(g) = 191.5 J/mol·K,
So of H2(g) = 130.6 J/mol·K.
N2(g) + 3H2(g) ßà 2NH3(g)