Question
A bullet of mass 50 grams is fired horizontally into a wooden block of mass 0.2kg. The wodden block is suspended from the ceiling by a long string as shown in the diagram. After impact the bullet is embedded in the block and bullet and the block swing together until the block is 0.12 m above its initial impact. find a) the velocity of the bullet and block just after impact
b) the velocity of the bullet just before impact.
b) the velocity of the bullet just before impact.
Answers
m g h = (1/2) m v^2
(.050 +.2)* 9.8 * .12 = .5 (.050+.2) v^2
1.176 = .5 v^2
v = 1.53 m/s for part a
momentum before = .05 Vo
momentum after = .25 *1.53
so
Vo = .25 * 1.53/.05
Vo = 7.67 m/s
(.050 +.2)* 9.8 * .12 = .5 (.050+.2) v^2
1.176 = .5 v^2
v = 1.53 m/s for part a
momentum before = .05 Vo
momentum after = .25 *1.53
so
Vo = .25 * 1.53/.05
Vo = 7.67 m/s