m g h = (1/2) m v^2
(.050 +.2)* 9.8 * .12 = .5 (.050+.2) v^2
1.176 = .5 v^2
v = 1.53 m/s for part a
momentum before = .05 Vo
momentum after = .25 *1.53
so
Vo = .25 * 1.53/.05
Vo = 7.67 m/s
A bullet of mass 50 grams is fired horizontally into a wooden block of mass 0.2kg. The wodden block is suspended from the ceiling by a long string as shown in the diagram. After impact the bullet is embedded in the block and bullet and the block swing together until the block is 0.12 m above its initial impact. find a) the velocity of the bullet and block just after impact
b) the velocity of the bullet just before impact.
1 answer
1 answer