a bullet of mass 20 grams is fired horizontally into suspended stationally Worden block of mass 380 grams with velocity of 200 m/s.what is the common velocity of bullet and block if the bullet embedded into the block,if the block and bullet experience a constant opposite force of 2N, find the time taken by them to com to rest?

Question

a bullet of mass 20 grams is fired horizontally into suspended stationally  Worden block of mass 380 grams with velocity of 200 m/s.what is the common velocity of bullet and block if the bullet embedded into the block,if the block and bullet experience a constant opposite force of 2N, find the time taken by them to com to rest?

ROSHAN MAINALI · Accepted Answer

I want to learn

R_scott · Answer

momentum is conserved ... bullet/block momentum = bullet momentum
... (380 + 20) V = 20 * 200
... find V ... then calculate the initial K.E. of the bullet/block

the energy of the bullet/block is dissipated by working against the 2 N force

find the distance ... f * d = K. E.

then find the time ... t = 2 * d / V

sjskk · Answer

how is f*d =1/2 mv^2

Suraj Gurung · Answer

how is f*d =1/2 mv^2 ? Ans : K.E = 1/2 mv^2 [ Since, K.E = Work i.e F*d ] F*d = 1/2 mv^2

Karij dhakal · Answer

Find the full ans no submit to the half ans