Question

A block of mass m1 = 28 kg rests on a wedge of angle θ = 47∘ which is itself attached to a table (the wedge does not move in this problem). An inextensible string is attached to m1, passes over a frictionless pulley at the top of the wedge, and is then attached to another block of mass m2 = 3 kg. The coefficient of kinetic friction between block 1 and the plane is μ = 0.8. The string and wedge are long enough to ensure neither block hits the pulley or the table in this problem, and you may assume that block 1 never reaches the table. take g to be 9.81 m/s2.


The system is released from rest as shown above, at t = 0.

(a) Find the magnitude of the acceleration of block 1 when it is released (in m/s2).

(b) How many cm down the plane will block 1 have traveled when 0.47 s has elapsed?

Answer 1

all i know is how to find acceleration. formula is (f - mu_1*m_b*g - mu_2*m_s*g)/m_b