Asked by henry
An aqueous solution of glucose is made by disolving 8.75 g of glucose in 100 mL of water. Calculate molarity, molality and the mole fraction
Answers
Answered by
DrBob222
M = mols/L. You get mols by grams/molar mass.
Now that you have mols, you can calculate m.
m = mols/kg solvent.
for X.
You have mols glucose.
Find mols H2O = grams/molar mass
Then total mols = mols glucose+mols H2O
Xglucose = mols glucose/total mols.
Post your work if you get stuck.
Now that you have mols, you can calculate m.
m = mols/kg solvent.
for X.
You have mols glucose.
Find mols H2O = grams/molar mass
Then total mols = mols glucose+mols H2O
Xglucose = mols glucose/total mols.
Post your work if you get stuck.
Answered by
Anonymous
`121
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