mols glucose = grams/molar mass. Solve for mols.
m = mols/Kg solvent
m = mols/0.475 = ?
Substitute m into
delta T = Kf*m and subtract from 0 C for the new freezing point
and delta T = Kb*m and add to 100 for the new boiling point.
Kf = 1.86 and Kb = 0.51
A glucose solution contains 55.0g of glucose C6H12O6 in 475g of water.
Compute the freezing point and boiling point of the solution. Assume a density of 1.00g/mL for water.
1 answer
1 answer