Asked by Mack
A runner weighs 560 N (about 130 lb), and 74% of this weight is water.
(a) How many moles of water are in the runner's body?
moles
(b) How many water molecules (H2O) are there?
molecules
(a) How many moles of water are in the runner's body?
moles
(b) How many water molecules (H2O) are there?
molecules
Answers
Answered by
Anonymous
runner's mass = 560N/g = 560/9.8 kg
weight of water =(560/9.8)*74% kg
=(560/9.8)*.74*1000 g
atomic mass of hydrogen=1g/mol
atomic mass of oxygen=16g/mol, so
atomic mass of water=2x1+16=18g/mol
moles water=(560/9.8)*.74/18
molecules=[moles water]*6x10^23
weight of water =(560/9.8)*74% kg
=(560/9.8)*.74*1000 g
atomic mass of hydrogen=1g/mol
atomic mass of oxygen=16g/mol, so
atomic mass of water=2x1+16=18g/mol
moles water=(560/9.8)*.74/18
molecules=[moles water]*6x10^23
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