An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 6635 J. What is the specific heat of the gas?

Answer 1

I believe this is done this way.
dE = q+w q is delta H and work is negative since the system did the work.
6635 = dH + (-346)
dH = 6635 + 346 = ?
dH = ? = mass x specific heat x (Tfinal-Tinitial)
Substitute and solve for specific heat.