1 answer
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plug and chug:
x = (-3Ā±ā(3^2-4*2*4))/(2*2)
= (-3Ā±ā(9-32))/4
= (-3Ā±iā23)/4
check:
2(-3/4+ā23/4 i)^2 + 3(-3/4+ā23/4 i) + 4
2(9/16 - 3ā23/8 i - 23/16) - 9/4 + 3ā23/4 i + 4
= 9/8 - 3ā23/4 i - 23/8 - 9/4 + 3ā23/4 i + 4
= 0
similarly for -3/4-ā23/4 i