Asked by Lucille
Can you please confirm that my answer is correct to this problem?
80x2^ - 96x + 27 =0
I am using the quadratic formula to solve... I would put the formula here but I can't put the square root sign in here.
My answer is -1.33 and -2.22
Is this correct? thank you
80x2^ - 96x + 27 =0
I am using the quadratic formula to solve... I would put the formula here but I can't put the square root sign in here.
My answer is -1.33 and -2.22
Is this correct? thank you
Answers
Answered by
Steve
well, did you try the values, to see whether they work?
80*(-1.33)^2 - 96(-1.33) + 27 = 296.192
Hmmm. I'd say nope.
So, too bad you didn't show your work...
80x2^ - 96x + 27 =0
Using the quadratic formula, since there are so many possible factors of 80 and 27,
x = (96±√(96^2-4*80*27)]/160
= (96±√576)/160
= (96±24)/160
= 120/160 or 72/160
= 3/4 or 9/20
so, the factorization must be
(4x-3)(20x-9) = 0
80*(-1.33)^2 - 96(-1.33) + 27 = 296.192
Hmmm. I'd say nope.
So, too bad you didn't show your work...
80x2^ - 96x + 27 =0
Using the quadratic formula, since there are so many possible factors of 80 and 27,
x = (96±√(96^2-4*80*27)]/160
= (96±√576)/160
= (96±24)/160
= 120/160 or 72/160
= 3/4 or 9/20
so, the factorization must be
(4x-3)(20x-9) = 0
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