A body moving with uniform acceleration has a velocity of 11.1 cm/s when its x coordinate is 4.6 cm. If its x coordinate 1.75 s later is −4.29 cm, what is the x-component of its acceleration? Answer in units of cm/s2. How would I set this up?

Answer 1

x(t)=xo+vix*time+1/2 a t^2

let toriginal=first sentence conditions.
V(t)=vo+at but at the first sentence, t is zero, so vo=11.1
so now go to the last position..
x(t)=xo+vix*time+1/2 a t^2
-4.29=0+11.1(1.75)-1/2 a (1.75)^2
solve for a.