A body moving with uniform acceleration has a velocity of 9.9 cm/s when its x coordinate is 1.28 cm. If its x coordinate 1.3 s later is -9.1 cm, what is the magnitude of its acceleration? Answer in units of cm/s2.

Answer 1

Start t=0 at the X = 1.28 cm location

X = (a/2)t^2 + 9.9 t + 1.28
-9.1 = (a/2)(1.3)^2 + 9.9*1.3 + 1.28
0.845 a = -9.1 -1.28 -12.87
a = -27.45 cm/s^2