Asked by Olivia
Find the derivative of the function.
G(y) =
(y − 1)3/
(y2 + 2y)7
G(y) =
(y − 1)3/
(y2 + 2y)7
Answers
Answered by
Steve
Assuming you mean
G(y) = (y-1)^3 / (y^2+2)^7
then just use the quotient rule to get
-(y-1)^2 (11y^2-14y-6) / (y^2+2)^8
G(y) = (y-1)^3 / (y^2+2)^7
then just use the quotient rule to get
-(y-1)^2 (11y^2-14y-6) / (y^2+2)^8
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