Asked by aarf
4. The initial concentration for the compounds involved in the reaction shown were determined to be [ClF(g)] = 0.5789 mol/L, [F2(g)] = 0.5980 mol/L, [Cl2(g)] = 0.05037 mol/L. Calculate the value of the equilibrium constant (Kc) at 2500 K if the equilibrium concentration of F2(g) was 0.5802 mol/L.
2ClF(g) = F2(g)+Cl2(g)
2ClF(g) = F2(g)+Cl2(g)
Answers
Answered by
DrBob222
See your other post above.
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