Question

The initial concentration of PCl5 was 0.1983 M. It was allowed to decompose at some temperature until equilibrium had been attained (see reaction below). What must be the equilibrium concentration of PCl3?
PCl5(g) ↔ PCl3(g) + Cl2(g) Kc = 0.0580

a. 0.1162 M

b. 0.0496 M

c. 0.0486 M

d. 0.0821 M
.......PCl5 --> PCl3 + Cl2
I...0.1983.......0......0
C.......-x.......x......x
E....0.1983-x....x......x

Substitute the E line into the Kc expression for PCl5 and solve for x.

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