Asked by Bridget
Lenth of a rectangle is 7ft longer than twice the width. If the rooms perimeter is 158ft, whay are the rooms dimensions?
Width
Length
Width
Length
Answers
Answered by
Jai
Represent the unknowns with variables:
Let x = width
Let 2x + 7 = length (according to the first statement)
Then we set up the equation. To set up, we need to recall that the perimeter of a rectangle is given by
P = 2L + 2W
where L is length and W is width.
We know that P = 158. Substituting,
158 = 2(2x + 7) + 2x
We solve for x:
158 = 4x + 14 + 2x
158 - 14 = 6x
144 = 6x
x = 144/6
x = 24 ft (width)
2x+7 = 55 ft (length)
hope this helps~ :3
Let x = width
Let 2x + 7 = length (according to the first statement)
Then we set up the equation. To set up, we need to recall that the perimeter of a rectangle is given by
P = 2L + 2W
where L is length and W is width.
We know that P = 158. Substituting,
158 = 2(2x + 7) + 2x
We solve for x:
158 = 4x + 14 + 2x
158 - 14 = 6x
144 = 6x
x = 144/6
x = 24 ft (width)
2x+7 = 55 ft (length)
hope this helps~ :3
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