Problem given:

14-4(2k+4) = -2(4-3k)

14-8k-16 = -8+12k

-8k-2 = -8+12k

plus 8k to each side ~~> -2 = -8+20k

plus 8 to each side ~~>6 = 20k

divide both sides by 20 ~~> 3/10 = k

4 answers

Now any UTex student worth his salt knows -2(4-3k)=-8+6k

Must have been Aggie thinking here.

with that change, it becomes
14-8k-16 = -8+6k
subtracting 6k from each side
-2-14k=-8
adding two to each side
-14k=-6
k=6/14 or 3/7
Thank you.

I missed this one, too -

A yard cleanup services charges a $380 fee plus $14 per hour. Another cleanup service charges a $260 fee plus $20 per hour. How long is a job for which the two companies' costs are the same?

380+14h = 260+20h

I got this after subtracting 260 from both sides: 120+14h = 20h

What should I do next?
chargefirst=380+14h
chargesecond=260+20h

if the charges are equal, then
380+14h=260+20h
subtract 14h from both sides
380=260+6h
subtract 260 from each side
120=6h
divide by 6 both sides
h=20 hours
Thank you!