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Air resistance acting on a falling body can be taken into account by the approximate relation for the acceleration. a= dv/dt= g...Asked by Rose
Air resistance acting on a falling body can be taken into account by the approximate relation for the acceleration: a= dv/dt = g - kv, where k is a constant. (a) Derive a formula for the velocity of the body as a function of time assuming it starts from rest (v=0 at t=0). [Hint: Change variables by setting u=g-kv.] (b) Determine an expression for the terminal velocity, which is the maximum value the velocity reaches.
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Answered by
Steve
using their hint, let u = g-kv
du/dt = -k dv/dt
-1/k du/dt = u
du/u = -k dt
log u = -kt
u = e^(-kt)
g-kv = e^(-kt)
v = (g-e^(-kt))/k
= g/k - 1/k e^(-kt)
So, max v is g/k as t->infinity
du/dt = -k dv/dt
-1/k du/dt = u
du/u = -k dt
log u = -kt
u = e^(-kt)
g-kv = e^(-kt)
v = (g-e^(-kt))/k
= g/k - 1/k e^(-kt)
So, max v is g/k as t->infinity
Answered by
蒋智超
The answer has a question that not aware of the acceleration has an initial value.
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