Asked by David S.
Air resistance acting on a falling body can be taken into account by
the approximate relation for the acceleration.
a= dv/dt= g-kv, where k is a constant. A) Derive a formula for the
velocity of the body as a function of time assuming it starts from rest (v=
0 at t=0)
B) Determine an expression for the terminal velocity, which is the
maximum value the velocity reaches
Use the separation of variables integration method.
dv/(g - kv) = dt
Integrate both sides startuing from t=0, when v = 0, and you get
t = (-1/k) [log (g - kv) - log g]
-kt = log (1 - kv/g)
e^-kt = 1 - kv/g
v = (g/k) (1 - e^-kt)
When t becomes very large, v -> g/k
you suck.
the approximate relation for the acceleration.
a= dv/dt= g-kv, where k is a constant. A) Derive a formula for the
velocity of the body as a function of time assuming it starts from rest (v=
0 at t=0)
B) Determine an expression for the terminal velocity, which is the
maximum value the velocity reaches
Use the separation of variables integration method.
dv/(g - kv) = dt
Integrate both sides startuing from t=0, when v = 0, and you get
t = (-1/k) [log (g - kv) - log g]
-kt = log (1 - kv/g)
e^-kt = 1 - kv/g
v = (g/k) (1 - e^-kt)
When t becomes very large, v -> g/k
you suck.
Answers
Answered by
David S.
I also didn't ask this. Again, somebody else did this.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.