Asked by Bryan

Find the Taylor series of f(x) = sin(x) at a = Pi/3.
Answered by Steve
sin(x-π/3) = sin(π/3) + 1/1! cos(π/3)(x-π/3) - 1/2! sin(π/3)(x-π/3)^2 ...
= √3/2 + 1/2 (x-π/3) - √3/4 (x-π/3)^2 ...
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