Asked by Riza

what value of m will make 4x-7y=5 and 9x+my=3 parallel?

a car leaves town A at 10:00 a.m. and travels at a constant speed of 40 kph towards a town B. After 30 minutes, a bus leaves town A and travels towards town B at a constant speed of 56 kph. at what time will the bus catch up with the car and how far will they be from town A?

two towns A and B are 35 km apart. Carlo starts cycling from A towards B at 1:00 p.m. at 20 kph intil he is 16 kilometers away from A, when he changes his speed so that he arrives at B at 3:00 p.m. his friend Arnold leaves town B at 1:30 pm and cycles towards town A at a constant speed of 25 kph.find: a) carlo's speed in the last part of the journey. b) the time when Arnold reachestown A. c) the time when the two men meet.

Answers

Answered by Graham
Parallel lines have the same gradient.

The gradient of the first line is: 4/7

The gradient of the second line is: -9/m

Thus: 4/7 = -9/m

Solve for: m = ...
Answered by Graham
distance = speed multiplied by time.

Measure all distance in kilometres and all time in hours.

The car travels: c(t) = 40 t
The bus travels: b(t) = 56 (t - 0.5)

Solve for t when c(t)=b(t)
Answered by Graham
find: a) carlo's speed in the last part of the journey.

Carlos travels 16km at 20kph for: 20/16 hours.

Thus Carlos travels the remaining (35-16) km for (2-20/16)hours at:
(35-16)/(2-20/16)kph.

b) the time when Arnold reaches town A.

Arnold travels 35km at 25kph for: (35/25)hours.
Thus arriving at his destination at:
1:30+(35/25)

c) the time when the two men meet.
At 1:00+20/16 (when Carlos changes speed 16 km from A), Arnold has traveled:
((1+20/15)-1.5)25 kilometres.

Thus they have already passed.

At the time t they meet:
Arnold has traveled (t-1.5)25 kilometres
Carlos has yet to travel: (3-t)(35-16)/(2-20/16)

Solve: (t-1.5)25 = (3-t)(35-16)/(2-20/16)
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