Ask a New Question

The current in a series circuit is 11.0 A. When an additional 11.0-Ω resistor is inserted in series, the current drops to 6.6 A. What is the resistance in the original circuit?

2 answers

R + 11 = (11A/6.6A)R 1.666R
1.666R - 1R = 11
0.666R = 11
R = 16.5 Ohms. = Original Resistance.

Correction: R + 11=(11A/6.6A)*R= 1.666R.

Similar Questions

The current in a series circuit is 11.7 A. When an additional 8.87-Ω resistor is inserted in series, the current drops to 6.83
1. 3 answers
The current in a series circuit is 11.0 A. When an additional 11.0-Ω resistor is inserted in series, the current drops to 6.6
1. 1 answer
1)Several resistors are connected in series. If a battery provides constant voltage in this circuit the addition of another
1. 2 answers
8. The current in a simple series circuit is 5 amp. When an additional resistance of 2 ohms is inserted in series, the current
1. 1 answer

more similar questions