Asked by sumit dubey
The current a series circuit in 5A when an additional resistance of 2 ohm is inserted the current drops to 4A voltage remaining same the original resistance of the circuit is
Answers
Answered by
Damon
original is r
v = 5 r
then later
same v = 4 (r+2)
so
5 r = 4 r + 8
r = 8 ohms
v = 5 r
then later
same v = 4 (r+2)
so
5 r = 4 r + 8
r = 8 ohms
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