Question

the class president plans to randomly select a committee of three people from three boys and five girls. How many committees are possible?

Answer 1

You are simply choosing 3 people from 8

that would be 8CHOOSE3 or C(8,3)
= 8!/(3!5!)
= 56

Answer 2

thanks

Answer 3

Since it is a combination and order does not matter. You would have 8 students taken 3 at a time.

MATH:
8C3= 8×7×6/3×2×1
=56 possible committees

Answer 4

By the way, the C in 8C3 does NOT stand for CHOOSE. It stands for combination.