Asked by Steven
can someone tell me wich one of the two answers for these two limits is correct?
lim (-1)^(n) = 1 or -1
n-> +infinity
lim (-1)^(n) = 1 or -1
n-> -infinity
Thanks in advance.
lim (-1)^(n) = 1 or -1
n-> +infinity
lim (-1)^(n) = 1 or -1
n-> -infinity
Thanks in advance.
Answers
Answered by
Reiny
depends on n
if n is even then the answer is +1
if n is odd you get -1
for:
lim (-1)^(n) = 1 or -1
n-> -infinity
is really the same as
lim 1/(-1)^(n)
so the same reasoning as above applies
if n is even then the answer is +1
if n is odd you get -1
for:
lim (-1)^(n) = 1 or -1
n-> -infinity
is really the same as
lim 1/(-1)^(n)
so the same reasoning as above applies
Answered by
Steven
1) I get it, except for
lim (-1)^(n) = ?
n-> +infinity
is infinity even or odd?
This is important because the result determines wheter the series that i was given is convergent or divergent.
2) in another excercise I encauntered the following problem:
is the following calculation with infinity allowed?:
lim (ln (n))^(1/n) = (ln (inf.))^(0)=1
n-> +inf.
Again txs for answering.
lim (-1)^(n) = ?
n-> +infinity
is infinity even or odd?
This is important because the result determines wheter the series that i was given is convergent or divergent.
2) in another excercise I encauntered the following problem:
is the following calculation with infinity allowed?:
lim (ln (n))^(1/n) = (ln (inf.))^(0)=1
n-> +inf.
Again txs for answering.
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