pH = 10
pOH = 14-10 = 4
pOH = -log(OH^-)
(OH^-) = 1 x 10^-4
Since NaOH is a strong base, then we want a concn of NaOH of 1 x 10^-4 M.
What molarity of NaOH would produce a pH of 10?
And how do you calculate it?
1 answer
And how do you calculate it?
1 answer
1 answer
2 answers
2 answers
2 answers