Asked by john

A battery of emf and negligible internal resistance is connected to two resistances R1 and R2 in series. What is the potential difference across R2?(a)E(R1+R2)/R2(b)E(R1+R2)/R1(c)ER2/R1+R2(d)ER1/R1+R2
Answered by Henry
c. ER2/(R1+R2)
Answered by Joseph
a)E(R1+R2)/R2
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