Asked by christina
Eliminate the parameter to find a cartesian equation
x= 1-t^2
y=t-2
-2 _<t _<2
known: -4 <(or=) y <(or =) 0
I got y= sq(x-1)+2
x= 1-t^2
y=t-2
-2 _<t _<2
known: -4 <(or=) y <(or =) 0
I got y= sq(x-1)+2
Answers
Answered by
Graham
Close.
Rearrange x = 1 - t^2:
t = ±√(1-x)
Substitute into: y = t - 2
y = -2 ± √(1-x)
--Alternatively--
Rearrange : y = t - 2
t = y + 2
Substitute into x = 1 - t^2
x = 1 - (y+2)^2
Thus:
x = -3 - 4y - y^2
Rearrange x = 1 - t^2:
t = ±√(1-x)
Substitute into: y = t - 2
y = -2 ± √(1-x)
--Alternatively--
Rearrange : y = t - 2
t = y + 2
Substitute into x = 1 - t^2
x = 1 - (y+2)^2
Thus:
x = -3 - 4y - y^2
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