Asked by Soren
Eliminate the parameter in the pair of parametric equations to find the corresponding rectangular question.
x=h+ asecQ
y=k+ tanQ
x=h+ asecQ
y=k+ tanQ
Answers
Answered by
Steve
secθ = (x-h)/a
tanθ = (y-k)
since sec^2 θ = 1+tan^2 θ
(x-h)^2/a^2 = 1+(y-k)^2
or,
(x-h)^2/a^2 - (y-k)^2 = 1
which is a horizontal hyperbola centered at (h,k).
tanθ = (y-k)
since sec^2 θ = 1+tan^2 θ
(x-h)^2/a^2 = 1+(y-k)^2
or,
(x-h)^2/a^2 - (y-k)^2 = 1
which is a horizontal hyperbola centered at (h,k).
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