Asked by Jackie
Eliminate the parameter x = t^2 - 1 and
y = t^2 + t
y = t^2 + t
Answers
Answered by
Damon
t^2 = x+1
y = x + 1 +/- (x+1)^.5
you can manipulate that further
y = x + 1 +/- (x+1)^.5
you can manipulate that further
Answered by
Steve
x^2 = t^4-2t^2+1
y^2 = t^4+2t^3+t^2
xy = t^4+t^3-t^2-1
x^2-2xy+y^2 = -3t^2 = -3(x+1)
x^2-2xy+y^2+3x+3 = 0
y^2 = t^4+2t^3+t^2
xy = t^4+t^3-t^2-1
x^2-2xy+y^2 = -3t^2 = -3(x+1)
x^2-2xy+y^2+3x+3 = 0
Answered by
Steve
oops
y-x = t+1
(y-x)^2 = t^2+2t+1
= 1/2(t^2+t) + 1/2 t^2 + 1
= y/2 + 1/2(t^2-1) + 3/2
= y/2 + x/2 + 3/2
(x-y)^2 = 1/2 (x+y+3)
y-x = t+1
(y-x)^2 = t^2+2t+1
= 1/2(t^2+t) + 1/2 t^2 + 1
= y/2 + 1/2(t^2-1) + 3/2
= y/2 + x/2 + 3/2
(x-y)^2 = 1/2 (x+y+3)
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