Asked by martha
Find the intercepts of the function f(x).
f(x) = (x - 2)2(x2 - 9)
f(x) = (x - 2)2(x2 - 9)
Answers
Answered by
bobpursley
f(x)=0 means x intercepts are
0=(x-2)^2*(x^2-9) so x intercepts are at x=2, 3, -3
Y intercept, when x=0
y=4*-9=-36
0=(x-2)^2*(x^2-9) so x intercepts are at x=2, 3, -3
Y intercept, when x=0
y=4*-9=-36