Question
A projectile fired upward from ground level is to reach a maximum height of 1,600 feet. What is its initial velocity?
Answers
Given:
s(t) = 1600
v(t) = 0
Let s(0) = 0
First find: t, in terms of v(0)
Using: s(t) = v(0)t-(1/2)gt^2
Then substitute for t to find v(0)
Using: v(t) = v(0) - gt
s(t) = 1600
v(t) = 0
Let s(0) = 0
First find: t, in terms of v(0)
Using: s(t) = v(0)t-(1/2)gt^2
Then substitute for t to find v(0)
Using: v(t) = v(0) - gt
Related Questions
A projectile is fired directly upward with a muzzle velocity of 860 feet per second from a height of...
If a projectile is fired straight upward from the ground with an inital speed of 96 feet per second,...
A projectile propelled straight upward from the ground is modeled by the function d(t)=-16t^2+304t....