Asked by Emily
Figure out the 35th derivative for xsinx. You have to do a few derivatives by hand to figure our a pattern and then predict the 35th one
Answers
Answered by
Steve
so, did you do that?
y = -0cosx + xsinx
y' = sinx + xcosx
y" = 2cosx - xsinx
y<sup>(3)</sup> = -3sinx - xcosx
y<sup>(4)</sup> = -4cosx + xsinx
Now we are back to n*cosx + xsinx. Watch how the signs change with period 4, as well as placement of sin/cos.
Looks to me like
y<sup>(35)</sup> = -35sinx - xcosx
y = -0cosx + xsinx
y' = sinx + xcosx
y" = 2cosx - xsinx
y<sup>(3)</sup> = -3sinx - xcosx
y<sup>(4)</sup> = -4cosx + xsinx
Now we are back to n*cosx + xsinx. Watch how the signs change with period 4, as well as placement of sin/cos.
Looks to me like
y<sup>(35)</sup> = -35sinx - xcosx
Answered by
Jeremy
Thanks guys I appreciate the help.
Answered by
Brian
Unfortunately I think you stopped one short. Should be 35sinx+xcosx.
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