Vi = 95,000m/3600 s = 26.4 m/s
v = Vi - a t
v = 0 at end of trip
0 = 26.4 - a t so t = 26.4/a
x = Vi t - .5 a t^2
60 = 26.4 t - .5 a t^2
60 = 26.4 (26.4/a) -.5 (a)(26.4^2)/a^2
60 = .5 (26.4)^2/a
a = 5.8 m/s^2 is deacceleration
A car is traveling at 95km/hr. the driver steps on the brakes and the car comes to a stop in 60m. What is the car's deceleration?
1 answer
1 answer