Question
The density of aluminum is 2.70 g/cm3, and the average mass for one aluminum atom is 4.48×10-23 g.
Five identical aluminum coins are found to displace a total of 2.50 mL of water when immersed in a graduated cylinder containing water.
How many atoms are present in one such aluminum coin?
Five identical aluminum coins are found to displace a total of 2.50 mL of water when immersed in a graduated cylinder containing water.
How many atoms are present in one such aluminum coin?
Answers
Steve
each coin is 0.50mL
.50mL * 2.70g/mL / 4.48*10^-23g/atom = 3.01*10^22 atoms
.50mL * 2.70g/mL / 4.48*10^-23g/atom = 3.01*10^22 atoms