Asked by Jessica

The density of aluminum is 2.70g/cm3. If a cube of aluminum weighs 13.5 grams whatis the length of the edge of the cube. I need help with the formula to figure this one out.
Answered by DrBob222
mass = volume x density
Solve for volume.
Then, since this is a cube, the length, width, and height are equal. So
volume = L x W x H but since L = W = H, then
volume = L x L x L. Solve for L.
Answered by Jessica
Hello Dr Bob,, I am still a little confused is this what it will look like 13.5/2.70=5 then take 5*5*5=125
Answered by DrBob222
Close but no cigar.
Volume = mass/density = 13.5/2.7 = 5.0 cc whis is ok to this point. Now,
volume = L x L x L
5 = L x L x L
5 = L<sup>3</sup>; therefore,
L = cube root 5 OR

L = 5<sup>1/3</sup>
(On your calculator, enter 5, then punch the y^x button, and type in .33333 (which is 1/3) and = to find the answer of 1.70997 which rounds to 1.71 cm to three significant figures.
Answered by Jessica
Thank you DR Bob
Answered by Anonymous
81 g
Answered by Anonymous
Aluminum has a density of 2.7 g/mL. What is the volume of an aluminum Cube that has a mass of 12.7 grams
Answered by Frank Mandhlokuwa
mass = volume x density
since this is a cube the length,width and height are
equal so volume =L ×W×H but since L=W=H
volume = mass/density
= 12,7÷2,7

= 4,703703704
4,703703704 = L^3
L = 1,675508565cm
Answered by OGE
I need help with d first chemistry question on thi page
There are no AI answers yet. The ability to request AI answers is coming soon!