Question

An athlete is training and is required to perform shuttle runs. From the starting position they sprint out to 10m (this takes 2 seconds).

Where would the maximum acceleration occur? Justify your answer.

Please help! Thankyou.

Answer 1

10 = (1/2) a t^2

20 = a (4)

a = 5 m/s^2

Answer 2

Thankyou, but I need to establish where within the run max acceleration occurs (what metre mark?)

Answer 3

I suspect if they turn around at the end, the max acceleration occurs there.

Answer 4

I think I know what you were looking for. Starting off where Damon left off,


Max acceleration occurs when the velocity=acceleration.

Vi=0m/s^2
Vf=5m/s and
a=5m/s^2
d=?

Solve for d.

Vf^2=Vi^2+2ad

(5m/s)^2=0+2(5m/s^2)d

25=10d
25/10=d

d=2.5m

The runner establishes max acceleration at the 2.5m mark in the race.


Hope I helped in time.