Asked by Andrew
In state-of-the-art vacuum systems, pressures as low as 1.00 x 10^-9 Pa are being attained. Calculate the number of molecules in a 1.90-m^3 vessel at this pressure and a temperature of 35.0°C.
Okay. So I know I have to use the Ideal Gas Law, PV = nRT, I then transformed it into being PV/RT = n.
1.00 X 10^-9 is my P.
1.90 m^3 is my V.
308.15 K is my T. (35 degrees C + 273.15)
How do I solve for how many molecules there are? What is my R?
Okay. So I know I have to use the Ideal Gas Law, PV = nRT, I then transformed it into being PV/RT = n.
1.00 X 10^-9 is my P.
1.90 m^3 is my V.
308.15 K is my T. (35 degrees C + 273.15)
How do I solve for how many molecules there are? What is my R?
Answers
Answered by
bobpursley
the number of molucles is n*avagradro's number
R? Pressure is Pa, volume in m^3, T i Kelvins... R has to be in Pa-M^3/mole.kelvins or 8.314
R? Pressure is Pa, volume in m^3, T i Kelvins... R has to be in Pa-M^3/mole.kelvins or 8.314
Answered by
Andrew
Okay so my equation was set up correctly and should read.. (1.00x10^-9)(1.90m^3)/(8.314x308.15) Correct? So my R would be 2.67724^-12?
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