CaCO3 ==> CaO + CO2
mols CaCO3 = grams/molar mass = 1000/100 = about 10 mols.
Covert mols CaCO3 to mols CaO using the equations in the balanced equation. That is about 10 mols CaO since CaCO3:CaO is 1:1.
Convert mols CaO to grams. g = mols x molar mass = about 10 x 56 = about 560 so the yield is 100% which means the yield for CO2 will be 100%.
Now convert mols CaCO3 to mols CO2 and convert to grams as in the CaO to find grams CO2.
Heat 1kg of CaCO3, get 560g of CaO.
Write the reactant equations and solve the mass of CO2 that born. The CaO is 100% pure.
Anyone help me, pls?
1 answer