Asked by Sheree'
CaCO3(s) + 2 HCl(aq) --> CaCl3(aq) + H2O(l) + CO2
It takes 19.26 mL of 0.6721 M HCl to completely react with the CaCO3. What is the mass of CaCO3 in the tablet?
didnt mean to cal you
It takes 19.26 mL of 0.6721 M HCl to completely react with the CaCO3. What is the mass of CaCO3 in the tablet?
didnt mean to cal you
Answers
Answered by
DrBob222
First correct the formula for calcium chloride to CaCl2.
mols HCl required = M x L = ?
mols CaCO3 = 1/2 that from the coefficients.
grams CaCO3 = mols CaCO3 x molar mass CaCO3
mols HCl required = M x L = ?
mols CaCO3 = 1/2 that from the coefficients.
grams CaCO3 = mols CaCO3 x molar mass CaCO3
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