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What is the empirical formula of a compound that is 14 g calcium, 11 g oxygen, and 0.7 g hydrogen? A. CaO2H B. Ca2OH2 C. CaOH D...Question
What is the empirical formula of a compound that is 14g calcium, 11g oxygen, and 0.7g hydrogen?
A. CaOH
B. Ca(OH)2
C. Ca2OH2
D. CaO2H
A. CaOH
B. Ca(OH)2
C. Ca2OH2
D. CaO2H
Answers
DrBob222
Convert g to mols.
Ca = 14/atomic mass Ca.
O = 11/atomic mass O.
H = 0.7/1 = 0.7
Then find the ratio of the elements to each other. The easy way to get started on that is to divide the smallest number by itself then follow suit with the other numbers. Don't round too much.
Ca = 14/atomic mass Ca.
O = 11/atomic mass O.
H = 0.7/1 = 0.7
Then find the ratio of the elements to each other. The easy way to get started on that is to divide the smallest number by itself then follow suit with the other numbers. Don't round too much.