What is the empirical formula for a compound which contains 67.1 percent zinc and the rest is oxygen

Answer 1

Take a 100 g sample which means
67.1 g Zn
100-67.1 = 32.9 g oxygen.

moles Zn = 67.1/atomic mass Zn = ?.
moles O = 32.9/16 = ?

Now find the ratio of the two elements to each other in small whole numbers with the smallest number no less than 1.00. The easy way to do that is to divide the smaller number of moles by itself thereby assuring you of obtaining 1.00 for that one. Then divide the other number by that same small number. Then round to whole numbers.

Answer 2

1000

Answer 3

What is the empirical formula for a compound which contains 67.1% zinc and the rest is oxygen

Answer 4

ZnO2