Asked by Wendy
What is the empirical formula for a compound which contains 67.1 percent zinc and the rest is oxygen
Answers
Answered by
DrBob222
Take a 100 g sample which means
67.1 g Zn
100-67.1 = 32.9 g oxygen.
moles Zn = 67.1/atomic mass Zn = ?.
moles O = 32.9/16 = ?
Now find the ratio of the two elements to each other in small whole numbers with the smallest number no less than 1.00. The easy way to do that is to divide the smaller number of moles by itself thereby assuring you of obtaining 1.00 for that one. Then divide the other number by that same small number. Then round to whole numbers.
67.1 g Zn
100-67.1 = 32.9 g oxygen.
moles Zn = 67.1/atomic mass Zn = ?.
moles O = 32.9/16 = ?
Now find the ratio of the two elements to each other in small whole numbers with the smallest number no less than 1.00. The easy way to do that is to divide the smaller number of moles by itself thereby assuring you of obtaining 1.00 for that one. Then divide the other number by that same small number. Then round to whole numbers.
Answered by
bob
1000
Answered by
RodrÃguez
What is the empirical formula for a compound which contains 67.1% zinc and the rest is oxygen
Answered by
Anonymous
ZnO2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.