Question
What is the empirical formula of a compound that contains 29% Na, 41% S, and 30% O by mass?
Answers
MathMate
Divide the percentages by the relative atomic mass (RAM) to get the relative number of atoms. Multiply by appropriate numbers to get whole numbers of atoms.
Na : 29/23 = 1.261
S : 41/32 = 1.281
O : 30/16 = 1.875
Now divide by 1.27 (average of 1.26 and 1.28)
Na : 1
S : 1
O : 1.48
Multiply by 2 to get whole numbers
Na : 2
S : 2
O 3
So the formula is
Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub>
The chemical name is sodium thiosulphate. It is used in the titration with iodine, fixation of photographs in the 'wet' darkroom, and many other uses.
Na : 29/23 = 1.261
S : 41/32 = 1.281
O : 30/16 = 1.875
Now divide by 1.27 (average of 1.26 and 1.28)
Na : 1
S : 1
O : 1.48
Multiply by 2 to get whole numbers
Na : 2
S : 2
O 3
So the formula is
Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub>
The chemical name is sodium thiosulphate. It is used in the titration with iodine, fixation of photographs in the 'wet' darkroom, and many other uses.