Asked by Emily
1) What is the amplitude, period, horizontal shift (relative to basic function), and vertical translation of the following: a) -3cos(x+ 3.14/4) and b) 2sin(x-3.14/2)+3
2) evaluate the following expressions: a) log2 cubed root of 16 b) log25 (1/125) c) e^2ln5 d) ln 1/the cubed root of e^5
2) evaluate the following expressions: a) log2 cubed root of 16 b) log25 (1/125) c) e^2ln5 d) ln 1/the cubed root of e^5
Answers
Answered by
Reiny
I will do 1 b) you do a)
y = 2 sin (x - π/2) + 3
amplitude = 2
period = 2π
phase shift = π/2 to the right
vertical translation : 3 units up
2. a) log<sub>2</sub>16^(1/3)
= log<sub>2</sub>(2^4)^(1/3)
= log<sub>2</sub>2^(4/3)
= (4/3) log<sub>2</sub> 2
= 4/3
b) log<sub>25</sub> 1/125
= log<sub>25</sub>1 - log<sub>25</sub>125
= 0 - log<sub>25</sub> 25^(3/2)
= -3/2
c) e^2ln5
= e^(ln 5^2))
= 5^2 = 25 , based on property that e^lnk = k
d) ln (1/( e^5)^(1/3)
= ln1 - ln e^(5/3)
= 0 - 5/3 lne
= -5/3
y = 2 sin (x - π/2) + 3
amplitude = 2
period = 2π
phase shift = π/2 to the right
vertical translation : 3 units up
2. a) log<sub>2</sub>16^(1/3)
= log<sub>2</sub>(2^4)^(1/3)
= log<sub>2</sub>2^(4/3)
= (4/3) log<sub>2</sub> 2
= 4/3
b) log<sub>25</sub> 1/125
= log<sub>25</sub>1 - log<sub>25</sub>125
= 0 - log<sub>25</sub> 25^(3/2)
= -3/2
c) e^2ln5
= e^(ln 5^2))
= 5^2 = 25 , based on property that e^lnk = k
d) ln (1/( e^5)^(1/3)
= ln1 - ln e^(5/3)
= 0 - 5/3 lne
= -5/3
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